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 2004 Technical Articles

Lithium Ion Batteries – Tasty But Deadly
(by Ian Jackson VK3BUF - Nov 2004)

There are lots of new electronic products out there which include Lithium-ion batteries as a power supply. But for all of that, not a great deal is known about them. They have become popular because of their high energy density. That is to say that you can jam a lot of energy within a very compact area, for very little weight. This makes them ideal for portable transceivers, cell phones and digital cameras. Almost twice the energy for half the weight/volume as traditional nicad cells. They also have really low self-discharge rates. (about half the rate of nicads) which makes them great for ‘emergency standby’ equipment.

However, if you are thinking of getting some to stuff into an old radio or appliance, then think again. They are a bit of a bugger to charge. They don’t behave the same way as any of the regular rechargeables, so put your old charger away.

  • For a start, you can’t charge them until a certain terminal voltage is reached, like most other cells. A nominal 3.7V cell should be charged to a 4.2V rail, but it will reach that voltage level and still only be half charged!
  • If you apply too high a terminal voltage you will permanently blow an integral over-voltage fuse inside the cell.
  • If you charge at the right voltage, but for too long (such as with trickle chargers) the internal chemistry moves around and Lithium finishes up re-plating itself on anode, followed by internal gassing and (ultimately) fire.
  • You can’t fast-charge them. Chargers that say they can, usually only achieve a 70% charge at best. (Typical charge times are 3 hours)
  • They should not be charged in sub-zero temperatures, or beyond 45º. (at 100º they will blow an internal safety fuse)
  • If you over discharge them, they will have a very short life. (never take the cell voltage below approx. 2.3V )
  • You can’t measure state-of-charge by measuring terminal voltage. The voltage varies too much with ambient temperature and individual brands of cells. (rule of thumb ~ 3.7V is roughly a half-charge, but don’t put money on it!
So, after that list of ‘don’ts’ you may well be wondering how they are charged. The trick is to manage them with a microprocessor so that the average punter can do their worst, without exposing the cells to harsh conditions. A cell should have 4.2 volts applied, then take a snapshot of the incoming current level. Keep on charging until the current demand has fallen to about 10% of the originally applied level, then halt the charge. The micro should be monitoring output current and voltage and temperature to prevent excessive charging & flattening of the cell. Most modern appliances designed for use with Lithium ion cells have an integral microprocessor to manage all of this for you.

Just be warned that if you try to replace them with nicad/NmHi/lead-acid or dry cells, or conversely, if you put a Lithium ion cell into an old appliance, be prepared for a dishonourable discharge.
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Fun with 2.4 GHz on the cheap
(by Paul VK3TGX - May 2004)

With the demise of the Galaxy 2.4GHz MDS pay TV system, grid dish antenna's very similar to this one have become available for nothing, they are fitted to many houses but are no longer used - just ask and someone will let you have theirs for nothing.

2.4 Ghz dish
Grid dish antenna

Now what to do with them, well recently 2.4GHz TV transmitter modules have become available at very cheap prices, especially if several club members can come together and make a bulk purchase, prices like $22 for a TX and $27 for an RX module can be achieved.

Another possible use is to connect them to wireless network cards in your PC, and share files and live 2 way video/audio contacts across town.

The biggest problem is getting the signals to the antenna, the secret to this is to put the transmitter/receiver modules on the back of the antenna's (in a water proof box of course) then run the video/data
signals back to your shack.

To run 2.4 GHz any distance up a co-axial cable requires something like helix coax, however if you put, say a video transmitter module (about the size of a box of matches) at the antenna, then video can be
run up to the antenna using cheap 75 ohm TV coax, with very little to no signal loss problems. Power can be run using figure 8 flex as the modules consume very little power (at 5V), so voltage drop
is not a problem.

In the first picture, the grid dish antenna was mounted on a light duty camera tripod for field work. This is a good way to experiment with simple short hop links before one gets too ambitions.       

PCB antenna
PCB antenna

The feed to the dish consists of a simple dipole antenna with a reflector element. The one above was made on printed circuit board, however you can use bits or brass rod, or heavy copper wire, just soldered together.       

PVC antenna
Pipe antenna

This one is made from brass rod, housed in PVC water pipe.

Come to this Friday's meeting and talk to John VK3YTV who made them.

Talk to Peter VK3KCG about how to get the video modules for a good price.

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Decibels Made Easy (Without Logarithms)
(
by Bruce Spratling, Jr. - Apr 2004)

Suppose your station has a transmitter that puts out 50 watts of power, a feed line that loses all but 40% of the power, a duplexer that loses half the power, and an antenna that produces enough gain to make the
signal 4 times as strong as a dipole antenna.  To find the effective radiated power of your station you need to multiply 50 watts times .4 (feed line loss) times .5 (duplexer loss) times 4 (antenna gain) = 40 watts.

Rather than multiply all these factors together, someone decided it would be good to represent them in a way that allows us to add them.  An increase of a factor of 10 is defined to be a 10 decibel  increase.  Decibels are abbreviated dB.  Two 10dB increases produces a 20dB increase, because we add decibel increases.

Two increases by a factor of 10 results in an increase of 10 X 10 = 100; therefore 20dB = 100.  Three 10dB increases is 30dB, which is 10 X 10 X 10 = 1000. 

Because we want to be able to add the dB increases, 0 dB is a factor of 1.  Multiplying something by 1 does not change it, just as adding 0 to something results in no change.

Decibels
  0
  10
  20
  30
Factor
  1
  10
  100
  1000

It’s easy to figure out the meaning of 10, 20, 30, 40... dB, but how about decibels less than 10?

Note that if we multiply 2 by itself 10 times, it generates the following: 2, 4, 8, 16, 32, 64, 128, 256, 512, 1024.

2 times itself 10 times is 1024, which is slightly more than 1000, which is 30dB.  3 added to itself 10 times is 30, and 30dB is a factor of 1000.  Therefore, 3dB represents a factor of (approximately) 2.

Another way to derive that 3dB represents a factor of 2 is this:  If we add 3dB to itself 3 times we get 9dB, which is less than, but close to, 10dB.  If we multiply 2 times itself 3 times we get 2X2X2=8, which is close to, but less than 10.  This is good because 9dB should be less than 10 (since 10 dB is 10).  We have to multiply 8 by 5/4 to equal 10, and we have to add 1dB to 9dB to equal 10dB.  Having 3dB = 2  will work if 1dB = 5/4.  Does 1 dB represent a factor of 5/4?  If we apply 1dB 3 times, we’ll have 3dB, which = 2.  (5/4)X(5/4)X(5/4) = 125/64, which is close to 2.  Therefore, a 3dB increase represents a 2 times increase, and 1 dB represents an increase of 1.25.

6dB = 3dB + 3dB.  A 3dB increase is a factor of 2, so 6dB = 2 X 2 = 4.  Similarly, 9 dB = 2 X 2 X 2 = 8.

So far we have:
Decibels
0
1
2
3
4
5
6
7
8
9
10
Factor
1
1.25
   
2
   
   
4
   
   
8
10
             

Let’s consider negative decibels.  -1dB changes 10dB to 9dB, which changes 10 to 8.  Therefore, -1 dB is .8, because .8 times 10 = 8.

To find 8dB, think of 8dB as 9dB – 1dB = 8 X .8 = 6.4.  To find 5dB, think of 5dB as 6dB - 1dB = 4 times .8 = 3.2.  Note that 5dB + 5dB = 10dB = 10.  Using 5dB = 3.2:  3.2 X 3.2 = 10.24, which is about 10.  To find 2dB, use 2dB = 3dB – 1dB = 2 X .8 = 1.6
  Decibels
  0
  1
  2
  3
  4
  5
  6
  7
  8
  9
  10
Estimated
Factor
1
1.25
1.6
2
2.5
3.2
4
5
6.4
8
10
Actual Value
1
1.26
1.58
1.99
2.51
3.16
3.985
5.01
6.31
7.94
10
% Error
 
.714
-.944
-.236
.475
-.178
-.473
.237
-1.41
-.708
0

You’ll notice from the chart that the results are all within 1.5%.

To summarize the system:

Realize that 3dB = 2, so 6dB = 4, and 9dB = 8.

You know the value for 3, 6, and 9dB (2, 4, 8).

To find 2, 5, or 8dB (1 less than 3dB, 6dB, or 9dB), use -1dB = .8.

If you want to know 4 or 7dB (1 more than 3dB or 6dB), use 1dB = 1.25.

To find fractions of 1dB, realize that 1dB represents a 25% increase, so .1dB is a 2.5% increase, .2dB is a 5% increase, .4dB is a 10% increase.  (This interpolation method isn’t exact, but it’s fairly close when dealing with such small values).

You can carry this further for hundredths of a decibel.  .01dB is one tenth of .1dB.  .1dB is 2.5%, so .01dB is .25%.  .04 dB is 1%.

An example:  Suppose an antenna has a gain of 17.68 dB.  How much increase is this?  Note that 17.68 = 10 + 7 + .68.  A 10 dB increase is a factor of 10.  A 7 dB increase is a factor of 5.  Therefore, a 17 dB increase is a factor of 10 X 5 = 50.  .6 dB is 15%, .08 dB is 2%, so .68 dB is about 17%.  50 X 1.17 = 58.5, so the antenna increases the signal strength by a factor of 58.5, the signal is 58.5 times as strong (the exact value is 58.61).

Another example:  An antenna’s signal is 25 times stronger than a dipole antenna.  How many decibels is this?  This is actually quite easy.  A 10 dB increase is a factor of 10.  Because 25 = 10 X 2.5, we still
have an increase of 2.5 to account for.  An increase of 2.5 is 4 dB, so the total increase = 10 dB + 4 dB = 14 dB (the exact value is 13.98 dB).

Suppose we have an increase of a factor of 30.  How many decibels is this?  30 = 10 X 3.  To multiply by 10 requires 10dB.  But, we need to add the decibels needed to multiply by 3.   4dB is 2.5, but we need 20% more (3 is 20% more than 2.5).  20% is about .8dB, so 30 = 14.8dB (the exact value is 14.77).

Well, that’s my little system for decibels, and as promised, I didn’t mention logarithms!
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GGREC IRLP 70cm Repeater Project
(by John VK3XJW - Jan 2004)

  

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